- Kp=Equilibrium constant in terms of partial pressure.
- Kc=Equilibrium constant in terms of concentration.
- Kx=Equilibrium constant in terms of mole fraction.
- Kn=Equilibrium constant in terms of number of moles.
- Kp and Kc are related as
**K**_{P}**= K**...........................(eq 1)_{C}(RT)^{∆n }

####
Relationship between **K**_{P} and **K**_{n}

_{P}

_{n}

...........................(eq 2)

From ideal gas equation,PV=nRT

=>P=n(RT/V)

Where,

**n**is the number of moles
So,

**P**_{A}=n_{A}(RT/v), P_{B}= n_{B}(RT/V), P_{C}=n_{C}(RT/V) and P_{D}=n_{D}**(RT/V)**

**Replacing equation 2 by the above value we get that,**

**[n**

_{C}(RT/V)]^{c }. [n_{D}(RT/V)]^{d }

**K**

_{p }**= -------------------------------------**

**[n**

_{A}(RT/V)]^{a }. [n_{B}(RT/V)]^{b }**n**

_{C}^{c }. n_{D}^{d }**= >**

**K**

_{p}**=**

**-------------- . ( RT/V )**

^{(c + d) – (a + b)}**n**

_{A}^{a}. n_{B}^{b}**= > K**

_{p}= K_{n}. (RT/V)^{∆n}##
= > K_{p} = K_{n} . (P_{T}/n_{T})
^{∆n }

∆n=number of gaseous moles of product – number of gaseous
moles of reactant

#### Relation between Kp and Kx

_{A = }**x**

_{A . }**P**

_{T}
P

Putting the values in whole equation:

##
= > K

_{B = }**x**_{B . }**P****P**

_{C = }**x**

_{C . }**P**

_{T}**P**

_{D = }**x**

_{D . }**P**

_{T}

Putting the values in whole equation:

(

**x**_{C . }**P**_{T })**. (**^{c}**x**_{D . }**P**)_{T}^{d}
K

**= ---------------------------------**_{P }
(

**x**_{A . }**P**)_{T}**. (**^{a}**x**_{B . }**P**)_{T}^{b}**x**

_{C}

^{c}

_{ . }**x**

_{D}

^{d}**= --------------**

_{ }**P**

_{ }

_{T}

^{(c+d) - (a+b)}**x**

_{A}

^{a}

_{ . }**x**

_{B}

^{b}##
= > K_{P }= K_{x }**(P**_{T}**)**** **^{∆n }

_{P }

_{x }

^{∆n }

**Q.Check your understanding.**

**N**

_{2}O_{4}(g)=2NO_{2}(g) ,Calculate K_{c }_{and}K_{x }for the given reaction for which Kp=0.157
Nyc

ReplyDeleteWe should now take a gander at reasons why a relationship would dependably have difficulties. There are bunches of relationship issues dispersed everywhere throughout the world. his secret obsession review

ReplyDeleteYou can find a beautiful Arab girl in any online dating service. Being one single Arab man is not fun.www.seksitreffit.cam

ReplyDeleteBut when they all will be equal

ReplyDeleteWhen number of moles in both product side and reactant side are equal,i.e. when ∆n=0, all the equilibrium constants become equal.

DeleteGlt

Delete1 hoga

DeleteI want to know relation between Kc an Kx .

ReplyDeleteBetween Kp ,Kc, and Kx which has dimension ?

ReplyDelete