Chemqueries: Equilibrium constant in terms of partial pressure.

### Equilibrium constant in terms of partial pressure.

Both KP and Kc  are equilibrium constants,but  Kc  is defined by molar concentration

#### Consider the following reversible reaction

aA(g) + bB(g) ⇔ cC(g) + dD(g)

• If equilibrium constant for the reaction  is expressed in terms of the molar concentration , • If the equilibrium involves gaseous species, then concentration may be expressed in terms of partial pressure of the reactants and products and it is represented as ......................... (eq1)

PA  ,  P ,  PC and PD  are  the partial pressure of A,B,C and D respectively.

#### Relationship between  KP and Kc  :

We know that ,for a ideal gas pressure is directly proportional to the concentration assuming volume and temperature constant.
So,    PV = nRT
Divide both sides by V,
P=(n/V)RT
P=CRT
Where,C is concentration
n is the number of moles
V is the volume
R is ideal gas constant,and
n/V is the molar concentration.
Thus the partial pressures of individual gases A, B, C and D are:
PA = [A]RT; PB = [B]RT; PC = [C]RT; PD = [D]RT
Substituting these value in equilibrium constant expression equation 1, we have  KP = KC (RT)(c+d)-(a+b)

KP = KC (RT)∆n
where ∆n = (c+d) – (a+b)
=number or gaseous moles of the product-number of gaseous moles of the reactant

1. 2. 